Measurement the Norton Equivalent for the circuit between node A and Ground in Multisim

    Determine by measurement the Norton Equivalent for the circuit between node A and Ground in Multisim

Sample Solution

   

Sure, here are the steps to determine by measurement the Norton Equivalent for the circuit between node A and Ground in Multisim:

  1. Open Multisim and create a new schematic.

  2. Draw the circuit between node A and Ground.

  3. Connect a current source (I) to node A and a voltage source (V) to Ground.

  4. Connect an ammeter (A) to measure the current flowing through the circuit.

  5. Connect a voltmeter (V) to measure the voltage across the circuit.

Full Answer Section

     
  1. Simulate the circuit and record the current and voltage readings.

  2. Use the following equation to calculate the Norton Equivalent current (I_N):

I_N = I - I_S

where I is the current flowing through the circuit and I_S is the short-circuit current.

  1. Use the following equation to calculate the Norton Equivalent resistance (R_N):

R_N = V / I_N

where V is the voltage across the circuit and I_N is the Norton Equivalent current.

  1. Repeat steps 6-8 for different values of the current source.

  2. Plot the Norton Equivalent current (I_N) versus the Norton Equivalent resistance (R_N).

  3. The Norton Equivalent for the circuit between node A and Ground is the point where the line intersects the y-axis.

Here is an example of how to determine by measurement the Norton Equivalent for the circuit between node A and Ground in Multisim:

  1. Open Multisim and create a new schematic.

  2. Draw the following circuit:

A
|
R1
|
B
|
V1
|
Ground

where R1 is a 1 kΩ resistor and V1 is a 1 V voltage source.

  1. Connect a current source (I) to node A and a voltage source (V) to Ground.

  2. Connect an ammeter (A) to measure the current flowing through the circuit.

  3. Connect a voltmeter (V) to measure the voltage across the circuit.

  4. Simulate the circuit and record the current and voltage readings.

  5. I = 1 mA and V = 0.99 V.

  6. I_S = 0 mA.

  7. I_N = I - I_S = 1 mA - 0 mA = 1 mA.

  8. R_N = V / I_N = 0.99 V / 1 mA = 990 Ω.

  9. Repeat steps 6-10 for different values of the current source.

  10. Plot the Norton Equivalent current (I_N) versus the Norton Equivalent resistance (R_N).

  11. The Norton Equivalent for the circuit between node A and Ground is the point where the line intersects the y-axis. The Norton Equivalent current is 1 mA and the Norton Equivalent resistance is 990 Ω.

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